B3-J^G1 A G2-H puts 2 greens together.ġ1. G3-H A B1-H forces a G3 or a B2 jump either of which puts like colors together.Ĩ. G2-J^B1 A B2-H move again puts 2 browns together.Ħ. G1-J^B2 A B3-H move puts 2 browns together.ĥ. A G1-H move would force either a B2-J^G1 or a G2-J^B1 move either of which puts 2 like colors together and you're stuck.Ĥ. B2-H A B3-J^B2 move would put B3 & B2 next to each other and you're stuck. The only other moves are G2-H & G3-J^G2 but those would put frogs next to each other and that's a no-no.ģ. B1-J^G1 This means the lead brown frog jumps over the lead green frog. The only other move is B1-H and that's an acceptable opening move also.Ģ. G1-H This means the lead green frog hops to the next rock. Notations: G=green frog, B=brown frog, 1=lead frog, 2=middle frog, 3=last frog J=jump, H=hop, ^=over.ġ. If you do get 2 frogs of the same color together outside the 3 end spots you're sunk and might as well just push REINICIAR to start over. Also don't make a hop or a jump that will force you to put 2 like color frogs together on the next move. I figured out that the secret is to avoid making a hop (move one space) or a jump (leap over another frog) that will put 2 frogs of the same color next to each other unless they are on the 3 end rocks with no opposite color frog there. I found a logic approach more understandable and useable. Example: First rock you'll click on is: Rock# 3 (click on Frog) Then, you count the rocks so many numbers over (using the numerical formula below), and click on the frog sitting on top of it.ģ. Count the numbers from left to right, using the numbers 1, 2, 3, 4, 5, 6, 7.Ģ.

Give each rock that a frog sits on a number. The best way that I have found to answer the 'Leap Frog Test', would be to do the following:ġ.

Frog leap solution